Question and Answers Forum

All Questions      Topic List

Mechanics Questions

Previous in All Question      Next in All Question      

Previous in Mechanics      Next in Mechanics      

Question Number 27677 by Tinkutara last updated on 12/Jan/18

Commented by Tinkutara last updated on 12/Jan/18

Commented by ajfour last updated on 14/Jan/18

Commented by ajfour last updated on 14/Jan/18

$$beforecollisionatB$$$$v=\sqrt{2\times 10\times 3}=\sqrt{60}m/s$$$$afterinelasticcollisionatB$$$$v=\sqrt{60}\cos 30°=\sqrt{60}\times \frac{\sqrt{3}}{2}=\sqrt{45}m/s.$$$$justbeforeleavingsecondincline$$$$speedatC:$$$$v_C^2=\sqrt{45+2\times 10\times 3}=\sqrt{105}m/s$$$$ifcollisionwereelastic$$$$aftercollisionatB,$$$$v_y=\sqrt{15}\cos 30°-\sqrt{45}\sin 30°$$$$=\frac{\sqrt{15}\times \sqrt{3}}{2}-\sqrt{45}\times \frac{1}{2}=0.$$

Commented by Tinkutara last updated on 14/Jan/18

Thanks very much!

Answered by ajfour last updated on 14/Jan/18

$$1\to \left(2\right)$$$$2\to \left(2\right)$$$$3\to \left(3\right)$$

Commented by Tinkutara last updated on 14/Jan/18

Thank you! I solved it.

Terms of Service

Privacy Policy

Contact: info@tinkutara.com