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Question Number 27706 by shivamgiri last updated on 13/Jan/18
thenumberofxϵ[0,2π]forwhich∣2sin4x+18cos2x−2cos4x+18sin2x∣=1
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![the number of xε[0,2π]for which∣(√)2sin^(4 ) x+18cos^2 x−(√(2cos^4 x+18sin^2 x))∣=1](Q27706.png)