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Question Number 27830 by çhëý böý last updated on 15/Jan/18

$$\underset{x\to \propto }{\lim }(x-\ln x)$$

Commented by abdo imad last updated on 15/Jan/18

$${lim}_{x->\propto }x-lnx={lim}_{x->\propto }x(1-\frac{ln\left(x\right)}{x})={lim}_{x->\propto }x=+\propto$$$$because{lim}_{x->\propto }\frac{ln\left(x\right)}{x}=0wesaythat{x}^{\alpha }defeatlnin\propto$$

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