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Question Number 27850 by v7277668420 last updated on 15/Jan/18

Answered by bmind4860 last updated on 15/Jan/18

$$a^2{sec}^2\theta -b^2({sec}^2\theta -1)=c^2$$$$afterrearrangingwehave$$$${sec}^2\theta =\frac{c^2-b^2}{a^2-b^2}$$$$\Rightarrow 1-{sin}^2\theta =\frac{a^2-b^2}{c^2-b^2}$$$$\Rightarrow {sin}^2\theta =\frac{c^2-a^2}{c^2-b^2}$$$$sin\theta =\pm \sqrt{\frac{c^2-a^2}{c^2-b^2}}$$

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