Question Number 27930 by tawa tawa last updated on 17/Jan/18
Commented by çhëý böý last updated on 20/Jan/18
![(1)=(4.0×10^4 )^2 =1.6×10^9 (2)=(4.0×10^4 )^(1/4) =14.14 K_c =(([HI]^2 )/([H_2 ][I_2 ])) K_c =(([NO]^2 [Cl_2 ])/([NOCl]^2 ))](Q28074.png)
$$\left(\mathrm{1}\right)=\left(\mathrm{4}.\mathrm{0}×\mathrm{10}^{\mathrm{4}} \right)^{\mathrm{2}} \:=\mathrm{1}.\mathrm{6}×\mathrm{10}^{\mathrm{9}} \\ $$$$\left(\mathrm{2}\right)=\left(\mathrm{4}.\mathrm{0}×\mathrm{10}^{\mathrm{4}} \right)^{\frac{\mathrm{1}}{\mathrm{4}}} =\mathrm{14}.\mathrm{14} \\ $$$$ \\ $$$${K}_{{c}} =\frac{\left[{HI}\right]^{\mathrm{2}} }{\left[{H}_{\mathrm{2}} \right]\left[{I}_{\mathrm{2}} \right]} \\ $$$${K}_{{c}} =\frac{\left[{NO}\right]^{\mathrm{2}} \left[{Cl}_{\mathrm{2}} \right]}{\left[{NOCl}\right]^{\mathrm{2}} } \\ $$
Commented by tawa tawa last updated on 20/Jan/18
$$\mathrm{God}\:\mathrm{bless}\:\mathrm{you}\:\mathrm{sir}. \\ $$