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Question Number 27930 by tawa tawa last updated on 17/Jan/18

Commented by çhëý böý last updated on 20/Jan/18

$$\left(1\right)={(4.0\times {10}^4)}^2=1.6\times {10}^9$$$$\left(2\right)={(4.0\times {10}^4)}^{\frac{1}{4}}=14.14$$$$$$$$K_c=\frac{{\left[HI\right]}^2}{\left[H_2\right]\left[I_2\right]}$$$$K_c=\frac{{\left[NO\right]}^2\left[{Cl}_2\right]}{{\left[NOCl\right]}^2}$$

Commented by tawa tawa last updated on 20/Jan/18

$$\mathrm{God}\mathrm{bless}\mathrm{you}\mathrm{sir}.$$

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