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Question Number 27976 by NECx last updated on 18/Jan/18
solve 2xx2+1<3x+12(x2+1)
Commented byabdo imad last updated on 18/Jan/18
duetox2+1>0(e)⇔2x<3x+12 ⇔4x−3x−1<0⇔x−1<0⇔x<1⇔x∈]−∝,1[
Answered by Rasheed.Sindhi last updated on 18/Jan/18
x2+1>0 Multiplyingby2(x2+1)toboth sides 2xx2+1<3x+12(x2+1)⇒4x<3x+1 x<1
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