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Question Number 27977 by NECx last updated on 18/Jan/18

∣2x+1∣≤2

2x+1∣⩽2

Answered by Rasheed.Sindhi last updated on 18/Jan/18

∣2x+1∣≤2  ±(2x+1)≤2  2x+1≤2 ∧ −2x−1≤2  x≤(1/2) ∧ x≥−(3/2)       −(3/2)≤x≤(1/2)

2x+1∣⩽2±(2x+1)22x+122x12x12x3232x12

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