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Question Number 28096 by tawa tawa last updated on 20/Jan/18

$$\underset{x\to \mathrm{\infty }}{\lim }\frac{{\mathrm{x}}^2}{\mathrm{x}-\mathrm{sinx}}$$

Commented by abdo imad last updated on 20/Jan/18

$$={lim}_{x\to \propto }\frac{x}{1-\frac{sinx}{x}}but/\frac{sinx}{x}/⩽\frac{1}{/x/}{}_{x\to \propto }\to 0$$$$\Rightarrow {lim}_{x\to \propto }\frac{x^2}{x-sinx}=lim{}_{x\to \propto }x=\propto .$$

Commented by tawa tawa last updated on 21/Jan/18

$$\mathrm{God}\mathrm{bless}\mathrm{you}\mathrm{sir}$$

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