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Question Number 28158 by abdo imad last updated on 21/Jan/18
calculate∫∫x2+y2⩽1dxdy3+x2+y2.
Answered by ajfour last updated on 21/Jan/18
x2+y2=r2dxdy=rdrdθ⇒I=∫02π[∫01(rdr3+r2)dθ=πln(43).
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