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Question Number 28174 by ktomboy1992 last updated on 21/Jan/18

$$\mathrm{if}\mathrm{the}\mathrm{sum}\mathrm{of}\mathrm{root}7\mathrm{x}+\mathrm{px}-\mathrm{q}=0\mathrm{is}7\mathrm{then}\mathrm{p}=$$$$??$$

Commented by Rasheed.Sindhi last updated on 21/Jan/18

$${7\mathrm{x}}^2+\mathrm{px}-\mathrm{q}=0$$$$\mathrm{Sum}\mathrm{of}\mathrm{the}\mathrm{roots}=-\frac{\mathrm{p}}{7}=7$$$$\mathrm{p}=-49$$

Commented by Rasheed.Sindhi last updated on 22/Jan/18

$$\mathrm{The}\mathrm{equation}\mathrm{is}\mathrm{linear},\mathrm{so}\mathrm{it}\mathrm{has}\mathrm{single}$$$$\mathrm{root}$$$$7\mathrm{x}+\mathrm{px}-\mathrm{q}=0$$$$\mathrm{x}(\mathrm{p}+7)=\mathrm{q}$$$$\mathrm{x}=\frac{\mathrm{q}}{\mathrm{p}+7}$$$$\mathrm{Sum}=\frac{\mathrm{q}}{\mathrm{p}+7}=7$$$$7\mathrm{p}+49=\mathrm{q}$$$$\mathrm{p}=\frac{\mathrm{q}-49}{7}$$

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