suppose one of the side of any box that can be carried onto an airplane must be less than 8m. Find the maximum value of such a box if the sum of the three sides can not exceed 46m.


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Question Number 28199 by NECx last updated on 21/Jan/18

$s u p p o s e o n e o f t h e s i d e o f a n y$ $b o x t h a t c a n b e c a r r i e d o n t o a n$ $a i r p l a n e m u s t b e l e s s t h a n 8 m .$ $F i n d t h e m a x i m u m v a l u e o f s u c h$ $a b o x i f t h e s u m o f t h e t h r e e s i d e s$ $c a n n o t e x c e e d 46 m .$
	Answered by mrW2 last updated on 22/Jan/18

	$V_{m a x} = a_{m a x} b_{m a x} c_{m a x} = 8 \times 8 \times 8 = 512 m^{3}$ $8 + 8 + 8 = 24 m < 46 m$ $Q u e s t i o n s e e m s t o h a v e a m i s t a k e .$
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