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Question Number 28508 by ajfour last updated on 26/Jan/18

Commented by ajfour last updated on 26/Jan/18

$$Q.28479\left(solution\right)$$

Answered by ajfour last updated on 26/Jan/18

$$Requiredarea=8\times AreaC\stackrel{⌢}{HM}$$$$=8(AreaO\stackrel{⌢}{HM}-△OHC)$$$$=8[\frac{\pi }{24}-\frac{1}{2}(\frac{\sqrt{3}}{2}-\frac{1}{2})\left(\frac{1}{2}\right)]$$$$=\frac{\pi }{3}-\sqrt{3}+1.$$$$=1-\sqrt{3}+\frac{\pi }{3}.$$

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