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Question Number 28518 by beh.i83417@gmail.com last updated on 26/Jan/18

Commented by beh.i83417@gmail.com last updated on 26/Jan/18

$$\mathit{a}\mathit{l}\mathit{l}\mathit{r}\mathit{a}\mathit{d}\mathit{i}\mathit{i}=1,\mathit{a}\mathit{b}=?$$$$\mathit{f}\mathit{i}\mathit{n}\mathit{d}\mathit{r}\mathit{a}\mathit{d}\mathit{i}\mathit{u}\mathit{s}\mathit{o}\mathit{f}\mathit{a}\mathit{c}\mathit{i}\mathit{r}\mathit{c}\mathit{l}\mathit{e}\left(orcircles\right)\mathit{t}\mathit{h}\mathit{a}\mathit{t}$$$$\mathit{t}\mathit{a}\mathit{n}\mathit{g}\mathit{e}\mathit{n}\mathit{t}\mathit{s}\mathit{t}\mathit{o}\mathit{t}\mathit{h}\mathit{i}\mathit{s}3\mathit{c}\mathit{i}\mathit{r}\mathit{c}\mathit{l}\mathit{e}\mathit{s}.$$

Commented by mrW2 last updated on 26/Jan/18

$$ab=r=1$$

Answered by mrW2 last updated on 27/Jan/18

Commented by mrW2 last updated on 27/Jan/18

$$bigcircle:$$$$R_1=r+\frac{2}{3}\times \sqrt{3}r=(1+\frac{2\sqrt{3}}{3})r\approx 2.15$$$$$$$$smallcircle:$$$$R_2=\frac{2}{3}\times \sqrt{3}r-1=(\frac{2\sqrt{3}}{3}-1)r\approx 0.15$$

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