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Question Number 28554 by naka3546 last updated on 27/Jan/18
(a−b)(c−d)=3(a−c)(b−d)=4(a−d)(b−c)=?
Answered by ajfour last updated on 27/Jan/18
a−b=3(c−d)...(i)a−c=4(b−d)...(ii)(ii)−(i):⇒b−c=3(b−c)+b−dor2(b−c)=d−b...(I)(i)−3(ii):−2a−b+3c=3c−3d−12b+12d⇒−2(a−d)=−11(b−d)...(II)(II)÷(I):a−db−c=−11.
Answered by mrW2 last updated on 27/Jan/18
a−b=3c−3d...(i)a−c=4b−4da−4b=c−4d...(ii)(i)−(ii)3b=2c+d⇒b=2c+d3⇒a=b+3c−3d=2c+d+9c−9d3=11c−8d3a−d=11c−8d−3d3=11(c−d)3b−c=2c+d−3c3=−(c−d)3⇒a−db−c=11(c−d)3−(c−d)3=−11
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