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Question Number 28624 by Joel578 last updated on 28/Jan/18

Commented by Joel578 last updated on 28/Jan/18

Find the value of  the given expression

Findthevalueofthegivenexpression

Commented by Tinkutara last updated on 28/Jan/18

1?

Commented by matikzone.tk last updated on 28/Jan/18

piye kabare pak joel?

piyekabarepakjoel?

Commented by Joel578 last updated on 29/Jan/18

baik

baik

Answered by moxhix last updated on 28/Jan/18

show: if  0<α,β,γ<π, α+β+γ=π  then tanα+tanβ+tanγ=tanαtanβtanγ .  //  tanα=−tan(π−α)=−tan(β+γ)      =−((tanβ+tanγ)/(1−tanβtanγ))  tanα(1−tanβtanγ)=−tanβ−tanγ  ∴ tanα+tanβ+tanγ=tanαtanβtanγ .  (∴((tanα+tanβ+tanγ)/(tanαtanβtanγ))=1)  //  now we set α=((2π)/(2017)), β=((1006π)/(2017)), γ=((1009π)/(2017)) .

show:if0<α,β,γ<π,α+β+γ=πthentanα+tanβ+tanγ=tanαtanβtanγ.//tanα=tan(πα)=tan(β+γ)=tanβ+tanγ1tanβtanγtanα(1tanβtanγ)=tanβtanγtanα+tanβ+tanγ=tanαtanβtanγ.(tanα+tanβ+tanγtanαtanβtanγ=1)//nowwesetα=2π2017,β=1006π2017,γ=1009π2017.

Commented by Joel578 last updated on 29/Jan/18

thank you very much

thankyouverymuch

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