A man pushes a box of 40kg up an incline plane of 15°,if the man applies a horizontal force of 200N and the box moves up the plane a distance of 20m at a constant velocity and the coefficient of friction is 0.10, find a)workdone by the man on the box. b)workdone against friction.


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Question Number 28644 by NECx last updated on 28/Jan/18

$A m a n p u s h e s a b o x o f 40 k g u p$ $a n i n c l i n e p l a n e o f 15 °, i f t h e m a n$ $a p p l i e s a h o r i z o n t a l f o r c e o f$ $200 N a n d t h e b o x m o v e s u p t h e$ $p l a n e a d i s t a n c e o f 20 m a t a$ $c o n s t a n t v e l o c i t y a n d t h e$ $c o e f f i c i e n t o f f r i c t i o n i s 0.10,$ $f i n d$ $a) w o r k d o n e b y t h e m a n o n t h e$ $b o x .$ $b) w o r k d o n e a g a i n s t f r i c t i o n .$
Commented by NECx last updated on 29/Jan/18

$p l e a s e h e l p$
Commented by Tinkutara last updated on 29/Jan/18

$W o r k d o n e b y m a n o n b o x = F \cos θ \times 20$ $= 200 \cos 15 ° \times 20 = 1000 \sqrt{2} (\sqrt{3} + 1)$ $f = μ N = μ (F \sin θ + m g \cos θ)$ $= 0.1 (200 \sin 15 ° + 40 g \cos 15 °)$
Commented by Tinkutara last updated on 29/Jan/18

Commented by NECx last updated on 30/Jan/18

$t h a n k y o u s o m u c h$
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