find the value of I=∫∫_D x^3 dxdy with D= {(x,y)∈R^2 /1≤x≤2 and x^2 −y^2 ≥1 }.


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Question Number 28685 by abdo imad last updated on 28/Jan/18
$find the value of I=∫∫_D x^3 dxdy with D= {(x,y)∈R^2 /1≤x≤2 and x^2 −y^2 ≥1 }.$
$f i n d t h e v a l u e o f I = \int \int_{D} x^{3} d x d y w i t h$ $D = {(x, y) \in R^{2} / 1 ⩽ x ⩽ 2 a n d x^{2} - y^{2} ⩾ 1} .$
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