Question and Answers Forum

All Questions      Topic List

Arithmetic Questions

Previous in All Question      Next in All Question      

Previous in Arithmetic      Next in Arithmetic      

Question Number 28932 by Rasheed.Sindhi last updated on 01/Feb/18

$$\mathrm{Determine}\mathrm{the}\mathrm{least}\mathrm{number}\mathrm{of}4\mathrm{digits},$$$$\mathrm{which}\mathrm{is}\mathrm{perfect}\mathrm{square}.$$$$\mathrm{Method}\mathrm{of}\mathrm{finding}\mathrm{is}\mathbf{required}.$$

Answered by mrW2 last updated on 01/Feb/18

$$x=n^2⩾1000$$$$n⩾\sqrt{1000}=31.6$$$$\Rightarrow n⩾32$$$$x_{min}={32}^2=1024$$$$$$$$x=n^2⩽9999$$$$n⩽\sqrt{9999}=99.99$$$$\Rightarrow n⩽99$$$$x_{max}={99}^2=9801$$$$$$$$32,33,...,99\Rightarrow 99-32+1=68$$$$i.e.therearetotally68$$$$4-digit-numberswhichare$$$$perfectsquare.$$

Commented by Rasheed.Sindhi last updated on 02/Feb/18

$$\mathbb{T}\mathrm{h}\alpha \mathrm{nks}-\mathrm{a}-\mathrm{lot}\mathbb{S}\mathrm{ir}!$$

Terms of Service

Privacy Policy

Contact: info@tinkutara.com