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Question Number 29049 by NECx last updated on 03/Feb/18

$$Provethat$$$$e^{i\pi }+1=0$$

Answered by Penguin last updated on 03/Feb/18

$$e^{i\theta }=\cos \left(\theta \right)+i\sin \left(\theta \right)$$$$\theta =\pi$$$$\therefore e^{i\pi }=-1+i\left(0\right)$$$$=-1$$

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