a(n,m)= { (m,(n≤0)),((a(n−1,m+2)),(n>0∧n≡0(mod 2))),((a(n−2,m−1)+nn),(n>0∧n≡1(mod 2)∧m≤0)),((a(m−1,n−1)+a(n−2,m−2)),(n>0∧n≡1(mod 2)∧m>0)) :} evaluate a(7,5)


Question and Answers Forum

All Questions Topic List
Relation and Functions Questions
Previous in All Question Next in All Question
Previous in Relation and Functions Next in Relation and Functions
Question Number 291 by 123456 last updated on 25/Jan/15

$a (n, m) = {\begin{cases} m & n ⩽ 0 \\ a (n - 1, m + 2) & n > 0 \land n \equiv 0 (\mod 2) \\ a (n - 2, m - 1) + n n & n > 0 \land n \equiv 1 (\mod 2) \land m ⩽ 0 \\ a (m - 1, n - 1) + a (n - 2, m - 2) & n > 0 \land n \equiv 1 (\mod 2) \land m > 0 \end{cases}$ $evaluate a (7, 5)$
	Answered by prakash jain last updated on 19/Dec/14

	$a (7, 5) = a (4, 6) + a (5, 3)$ $= a (3, 8) + a (2, 4) + a (3, 1)$ $= a (7, 2) + a (1, 6) + a (1, 6) + a (0, 2) + a (1, - 1)$ $a (1, 6) = a (5, 0) + a (- 1, 4)$ $= a (3, - 1) + 25 + 4$ $= a (1, - 2) + 6 + 25 + 4$ $= a (- 1, - 3) + 1 + 6 + 25 + 4$ $= - 3 + 1 + 6 + 25 + 4 = 33$ $a (0, 2) = 2$ $a (1, - 1) = a (- 1, - 3) + 1 = - 3 + 1 = 2$ $a (7, 2) = a (1, 6) + a (5, 0)$ $= a (5, 0) + a (- 1, 4) + a (5, 0)$ $= 29 + 4 + 29 = 62$ $a (7, 5) = 62 + 33 + 33 + 2 + 2 = 132$
Terms of Service
Privacy Policy
Contact: info@tinkutara.com

Question and Answers Forum