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Question Number 29241 by mondodotto@gmail.com last updated on 05/Feb/18

Answered by ajfour last updated on 05/Feb/18

k(x^2 +y^2 )+y^2 +4y−4x^2 −4x+3=0 coeff. of x^2 =coeff. of y^2 ⇒ k−4 =k+1 ⇒ k→∞ then eq. of circle is x^2 +y^2 =0 centre is the origin, radius =0 .

k(x2+y2)+y2+4y−4x2−4x+3=0coeff.ofx2=coeff.ofy2⇒k−4=k+1⇒k→∞theneq.ofcircleisx2+y2=0centreistheorigin,radius=0.

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