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Question Number 29265 by tawa tawa last updated on 06/Feb/18

$$\mathrm{An}\mathrm{electric}\mathrm{pump}\mathrm{with}\mathrm{efficiency}\mathrm{of}70\mathrm{\%}\mathrm{raises}\mathrm{water}\mathrm{to}\mathrm{a}\mathrm{height}\mathrm{of}15\mathrm{m}$$$$.\mathrm{If}\mathrm{water}\mathrm{is}\mathrm{delivered}\mathrm{at}\mathrm{the}\mathrm{rate}\mathrm{of}350{\mathrm{dm}}^3\mathrm{per}\mathrm{minute}.$$$$\left(\mathrm{i}\right)\mathrm{what}\mathrm{is}\mathrm{the}\mathrm{power}\mathrm{rating}\mathrm{of}\mathrm{the}\mathrm{pump}?(\mathrm{mass}\mathrm{of}1{\mathrm{dm}}^3=1\mathrm{kg})$$$$\left(\mathrm{ii}\right)\mathrm{what}\mathrm{is}\mathrm{the}\mathrm{energy}\mathrm{lost}\mathrm{by}\mathrm{the}\mathrm{pump}?(\mathrm{g}=10\mathrm{m}/{\mathrm{s}}^2)$$$$(\mathrm{Answer}:1250\mathrm{W}.22.5\mathrm{KJ})$$

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