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Question Number 29268 by tawa tawa last updated on 06/Feb/18

$$\mathrm{A}\mathrm{man}\mathrm{moves}20\mathrm{m}\mathrm{North},\mathrm{then}12\mathrm{m}\mathrm{East}\mathrm{and}\mathrm{finally}15\mathrm{m}\mathrm{South}.\mathrm{His}$$$$\mathrm{displacement}\mathrm{from}\mathrm{the}\mathrm{starting}\mathrm{point}\mathrm{is}\mathrm{now}$$$$\left(\mathrm{a}\right)13\mathrm{m}\left(\mathrm{b}\right)27\mathrm{m}\left(\mathrm{c}\right)47\mathrm{m}\left(\mathrm{d}\right)23\mathrm{m}$$

Commented by Rasheed.Sindhi last updated on 06/Feb/18

$$\left(\mathrm{a}\right)13\mathrm{m}$$$$\mathrm{Net}\mathrm{distance}\mathrm{along}\mathrm{north}20-15=5\mathrm{m}$$$$\mathrm{Distance}\mathrm{to}\mathrm{the}\mathrm{east}12$$$$\mathrm{Displacement}\sqrt{5^2+{12}^2}=\sqrt{169}=13\mathrm{m}$$

Commented by tawa tawa last updated on 06/Feb/18

$$\mathrm{God}\mathrm{bless}\mathrm{you}\mathrm{sir}$$

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