Question and Answers Forum

All Questions      Topic List

Logic Questions

Previous in All Question      Next in All Question      

Previous in Logic      Next in Logic      

Question Number 29308 by tawa tawa last updated on 07/Feb/18

$$\mathrm{Solve}:{\mathrm{w}}^3=-16$$

Answered by Tinkutara last updated on 07/Feb/18

$$\frac{w^3}{-16}=1$$$$\frac{w}{-2^{4/3}}=1,\omega ,{\omega }^2$$$$w=-2^{4/3},-2^{4/3}\omega ,-2^{4/3}{\omega }^2$$

Answered by sma3l2996 last updated on 07/Feb/18

$$w^3=-16=16i^2=16e^{i\pi }$$$$w_k=2\sqrt[3]{2}{e}^{i\left(\frac{2k+1}{3}\right)\pi }$$$$w_0=2\sqrt[3]{2}{e}^{i\pi /3};w_1=-2\sqrt[3]{2};w_2=2\sqrt[3]{2}{e}^{-i\pi /3}$$

Terms of Service

Privacy Policy

Contact: info@tinkutara.com