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Question Number 29324 by mondodotto@gmail.com last updated on 07/Feb/18

Answered by ajfour last updated on 07/Feb/18

$$e^y\left(\frac{dy}{dx}\right)=3x^2+{\tan }^{-1}y+\left(\frac{x}{1+y^2}\right)\frac{dy}{dx}$$$$\frac{dy}{dx}=\frac{3x^2+{\tan }^{-1}y}{[e^y-\frac{x}{1+y^2}]}.$$

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