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Question Number 29454 by prof Abdo imad last updated on 08/Feb/18

f is a function increasing and C^1 on [a,b] prove   ∫_(f(a)) ^(f(b))  f^(−1) (t)dt = ∫_a ^b  x f^′ (x)dx

$${f}\:{is}\:{a}\:{function}\:{increasing}\:{and}\:{C}^{\mathrm{1}} {on}\:\left[{a},{b}\right]\:{prove} \\ $$$$\:\int_{{f}\left({a}\right)} ^{{f}\left({b}\right)} \:{f}^{−\mathrm{1}} \left({t}\right){dt}\:=\:\int_{{a}} ^{{b}} \:{x}\:{f}^{'} \left({x}\right){dx}\: \\ $$

Commented by prof Abdo imad last updated on 27/Feb/18

let put f^(−1) (t)=x ⇒t=f(x)⇒dt =f^′ (x)dx  ∫_(f(a)) ^(f(b))  f^(−1) (t)dt= ∫_a ^(b )  x f^′ (x)dx .

$${let}\:{put}\:{f}^{−\mathrm{1}} \left({t}\right)={x}\:\Rightarrow{t}={f}\left({x}\right)\Rightarrow{dt}\:={f}^{'} \left({x}\right){dx} \\ $$$$\int_{{f}\left({a}\right)} ^{{f}\left({b}\right)} \:{f}^{−\mathrm{1}} \left({t}\right){dt}=\:\int_{{a}} ^{{b}\:} \:{x}\:{f}^{'} \left({x}\right){dx}\:. \\ $$

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