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Question Number 29490 by Victor31926 last updated on 09/Feb/18
AgasexpandsaccordingtothelawPV=K(constant).Initialy,v=1000cubicmetresandp=40N/m2.Ifthepressureisdecreasedattherateof5N/m2/min.findtherateatwhichthegasisexpandingwhenitsvolumeis2000cubicmetres.
Answered by Rasheed.Sindhi last updated on 09/Feb/18
PV=KWhenV=1000m3andP=40N/m2K=40N/m2×1000m3=40000NmWhenV=2000m3P=KV=40000Nm2000m3=20N/m2PerminutechangeinP,whenV=2000m3Pchangesfrom20N/m2to15N/m2Changedvolume=KChangedpressure=40000Nm15N/m2=266623m3Changeinvolume(inoneminute)=266623m3−2000m3=66623m3/min(expanding)Pleaseconfirmtheanswer.
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