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Question Number 29498 by ajfour last updated on 09/Feb/18
Commented by ajfour last updated on 09/Feb/18
Relatelinearacceleration,withposition,velocity,angularvelocity,andangularacceleration.
Answered by ajfour last updated on 09/Feb/18
Acceleration:__________________ds¯=rxy(−sinψi^+cosψj^)dψ+ryz(−sinθj^+cosθk^)dθ+rzx(−sinϕk^+cosϕi^)dϕ+dr(xi^+yj^+k^r)=(zdϕ−ydψ)i^+(xdψ−zdθ)j^+(ydθ−xdϕ)k^+drr(xi^+yj^+k^)⇒ds¯=[i^j^k^dθdϕdψxyz]+drr(xi^+yj^+zk^)ds¯dt=v¯=ω¯×r¯+1r(drdt)r¯⇒a¯=α¯×r¯+ω¯×v¯−1r2(drdt)2r¯+1r(d2rdt2)r¯+1r(drdt)v¯a¯=α¯×r¯+ω¯×(ω¯×r¯)+1r(drdt)(ω¯×r¯)−1r2(drdt)2r¯+1r(d2rdt2)r¯++1r(drdt)(ω¯×r¯)+1r2(drdt)2r¯a¯=α¯×r¯+ω¯×(ω¯×r¯)+1r(d2rdt2)r¯+2r(drdt)(ω¯×r¯)−−−−−−−−−−−−−−−
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