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Question Number 29541 by naka3546 last updated on 09/Feb/18

Commented by naka3546 last updated on 09/Feb/18

$$ProvethatDFisperpendiculartoIC.$$

Commented by ajfour last updated on 09/Feb/18

Commented by ajfour last updated on 09/Feb/18

$$\tan \theta =\frac{c-a\cos \alpha -a\sin \alpha }{a\cos \alpha -a\sin \alpha }$$$$\tan \varphi =\frac{b\cos \beta -b\sin \beta }{c-b\cos \beta -b\sin \beta }$$$$andsincea\cos \alpha +b\cos \beta =c$$$$alsoa\sin \alpha =b\sin \beta$$$$therefore\tan \mathit{\theta }=\tan \mathit{\varphi }$$$$soDF\mathrm{\perp }toIC.$$

Commented by mrW2 last updated on 09/Feb/18

Great!

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