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Question Number 2968 by Karting7442 last updated on 01/Dec/15

Powers of Monomials       Alg.    (0.6p^5 )^3

PowersofMonomialsAlg.(0.6p5)3

Answered by Filup last updated on 02/Dec/15

=0.6^3 p^(15)     0.6=(6/(10))⇒0.6^2 =((36)/(100))=0.36    =0.36p^(15)

=0.63p150.6=6100.62=36100=0.36=0.36p15

Commented by Yozzi last updated on 02/Dec/15

0.6^3 =0.36×0.6=0.216

0.63=0.36×0.6=0.216

Commented by Filup last updated on 03/Dec/15

oops I missread

oopsImissread

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