Question Number 29680 by 803jaideep@gmail.com last updated on 11/Feb/18
$$\mathrm{i}^{\mathrm{i}\:} \:\:\mathrm{what}\:\mathrm{is}\:\mathrm{iota}\:\mathrm{to}\:\mathrm{power}\:\mathrm{iota} \\ $$
Answered by sma3l2996 last updated on 11/Feb/18
$${i}^{{i}} =\left({e}^{{i}\pi/\mathrm{2}} \right)^{{i}} ={e}^{ā\pi/\mathrm{2}} \\ $$
Commented by 803jaideep@gmail.com last updated on 11/Feb/18
$$\mathrm{hm}\:\mathrm{rit}... \\ $$