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Question Number 29700 by 803jaideep@gmail.com last updated on 11/Feb/18

$${32}^{{32}^{32}}/7...\mathrm{find}\mathrm{remainder}$$

Answered by Tinkutara last updated on 13/Feb/18

Commented by Tinkutara last updated on 13/Feb/18

Proof by Binomial Theorem.

Commented by rahul 19 last updated on 13/Feb/18

$$\mathrm{this}\mathrm{seems}\mathrm{correct}.$$

Commented by 803jaideep@gmail.com last updated on 14/Feb/18

$$2^{5^{32}}\ne 2^{160}\mathrm{as}{5}^{32}\ne 160$$

Commented by Tinkutara last updated on 14/Feb/18

$$Insecondline$$$${32}^{32}={\left(2^5\right)}^{32}=2^{160}iscorrect.$$

Commented by 803jaideep@gmail.com last updated on 14/Feb/18

$$\mathrm{kk}...\mathrm{thn}\mathrm{i}\mathrm{misunderstood}\mathrm{it}$$

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