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Question Number 29778 by puneet1789 last updated on 12/Feb/18
Answered by Giannibo last updated on 12/Feb/18
f(x)+f′(x)⩽1exf(x)+exf′(x)⩽ex∫01(exf(x))′dx⩽∫01exdx[exf(x)]01⩽[ex]01ef(1)−f(0)⩽e−1f(1)⩽e−1e
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