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Question Number 29880 by tawa tawa last updated on 13/Feb/18

Commented by ajfour last updated on 13/Feb/18

Commented by ajfour last updated on 13/Feb/18

$$F\cos \alpha -f-mg\sin \alpha =ma$$$$\Rightarrow f=F\cos \alpha -ma-mg\sin \alpha$$$$=200\cos 20°-1.5\times 0.4-15\sin 20°$$$$\Rightarrow \mathit{f}=182.2\mathit{N}$$$$\mu N=\mu (mg\cos \alpha +F\sin \alpha )=f$$$$\mu =\frac{f}{mg\cos \alpha +F\sin \alpha }$$$$\mu =\frac{200\cos 20°-0.6-15\sin 20°}{15\cos 20°+200\sin 20°}$$$$\Rightarrow \mathit{\mu }=2.208$$

Commented by tawa tawa last updated on 13/Feb/18

$$\mathrm{God}\mathrm{bless}\mathrm{you}\mathrm{sir}.\mathrm{i}\mathrm{really}\mathrm{appreciate}$$

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