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Question Number 30094 by Tinkutara last updated on 16/Feb/18

Commented by mrW2 last updated on 28/Feb/18

$$Thethinfilmofwaterstandsin$$$$underpressureduetosurfacetension,$$$$seediagram.$$$$R\cos \theta =\frac{d}{2}$$$$\Rightarrow R=\frac{d}{2\cos \theta }$$$$\mathrm{\Delta }p=\frac{S}{R}=\frac{2S\cos \theta }{d}$$$$F=\mathrm{\Delta }pA=\frac{2AS\cos \theta }{d}$$$$with\theta =0°$$$$\Rightarrow F=\frac{2AS}{d}$$

Commented by Tinkutara last updated on 01/Mar/18

$$But\mathrm{\Delta }pshouldbe\frac{2S}{R}?$$

Commented by mrW2 last updated on 28/Feb/18

Commented by mrW2 last updated on 01/Mar/18

$$Nosir!$$$$2R\times \mathrm{\Delta }p=2S$$$$\Rightarrow \mathrm{\Delta }p=\frac{S}{R}$$

Commented by Tinkutara last updated on 01/Mar/18

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