Question Number 30176 by abdo imad last updated on 17/Feb/18
$${prove}\:{that}\:\:{v}_{{n}} =\:\sum_{{k}=\mathrm{1}} ^{{n}} \:\:\:\frac{\mathrm{1}}{\mathrm{2}{n}+\mathrm{2}{k}\:+\mathrm{1}}\:{is}\:{convergente}. \\ $$
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Question Number 30176 by abdo imad last updated on 17/Feb/18 | ||
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$${prove}\:{that}\:\:{v}_{{n}} =\:\sum_{{k}=\mathrm{1}} ^{{n}} \:\:\:\frac{\mathrm{1}}{\mathrm{2}{n}+\mathrm{2}{k}\:+\mathrm{1}}\:{is}\:{convergente}. \\ $$ | ||