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Question Number 30340 by mondodotto@gmail.com last updated on 20/Feb/18

	Answered by mrW2 last updated on 20/Feb/18
	$4^x =16x e^(xln 4) =16x xe^(−xln 4) =(1/(16)) (−xln 4)e^(−xln 4) =−((ln 4)/(16)) ⇒−xln 4=W(−((ln 4)/(16))) ⇒x=−((W(−((ln 4)/(16))))/(ln 4))≈ { ((−((−0.0953)/(ln 4))=0.0687)),((−((−3.7741)/(ln 4))=2.7224)) :}$
	$4^{x} = 16 x$ $e^{x \ln 4} = 16 x$ ${x e}^{- x \ln 4} = \frac{1}{16}$ $(- x \ln 4) e^{- x \ln 4} = - \frac{\ln 4}{16}$ $\Rightarrow - x \ln 4 = W (- \frac{\ln 4}{16})$ $\Rightarrow x = - \frac{W (- \frac{\ln 4}{16})}{\ln 4} \approx {\begin{cases} - \frac{- 0.0953}{\ln 4} = 0.0687 \\ - \frac{- 3.7741}{\ln 4} = 2.7224 \end{cases}$
	Commented by mondodotto@gmail.com last updated on 21/Feb/18

	$sir thanx a lot$
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