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Question Number 30418 by abdo imad last updated on 22/Feb/18

integrate y^′  −2xy = sinx e^x^2   with y(0)=1.

$${integrate}\:{y}^{'} \:−\mathrm{2}{xy}\:=\:{sinx}\:{e}^{{x}^{\mathrm{2}} } \:{with}\:{y}\left(\mathrm{0}\right)=\mathrm{1}. \\ $$

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