Question Number 30499 by abdo imad last updated on 22/Feb/18
$${let}\:{put}\:{F}\left({x}\right)=\:\int_{\mathrm{0}} ^{{x}} \:\sqrt{{tant}}\:\:{dt}\:{with}\:{x}>\mathrm{0}\:\:{find}\:{F}\left({x}\right). \\ $$
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Question Number 30499 by abdo imad last updated on 22/Feb/18 | ||
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$${let}\:{put}\:{F}\left({x}\right)=\:\int_{\mathrm{0}} ^{{x}} \:\sqrt{{tant}}\:\:{dt}\:{with}\:{x}>\mathrm{0}\:\:{find}\:{F}\left({x}\right). \\ $$ | ||