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Question Number 30553 by abdo imad last updated on 23/Feb/18
findlimx→0(1+sinx)x−(1+x)sinx.
Commented by Cheyboy last updated on 23/Feb/18
bydirectsubtitutionlimx→0(1+0)0−(1+0)0=0
Commented by abdo imad last updated on 23/Feb/18
forgivetheQisfindlimx→0(1+sinx)x−(1+x)sinxx.
Commented by rahul 19 last updated on 23/Feb/18
simplyusehospitalrule.
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