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Question Number 30657 by NECx last updated on 23/Feb/18

$$\underset{x\to \mathrm{\infty }}{\lim }{e}^{-\frac{x^2}{2}}$$

Commented by Cheyboy last updated on 23/Feb/18

$$\underset{x\to \mathrm{\infty }}{\lim }{e}^{-\frac{{\mathrm{\infty }}^2}{2}}$$$$$$$$\underset{x\to \mathrm{\infty }}{\lim }{e}^{-\mathrm{\infty }}$$$$$$$$\underset{x\to \mathrm{\infty }}{\lim }\frac{1}{e^{\mathrm{\infty }}}$$$$Asxincreasesapproching\Rightarrow \mathrm{\infty }$$$$\frac{1}{e^{\mathrm{\infty }}}approches0$$$$$$$$Hence\underset{x\to \mathrm{\infty }}{\lim }\frac{1}{e^{\mathrm{\infty }}}=0$$$$$$

Commented by NECx last updated on 25/Feb/18

$$thankyousir.$$

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