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Question Number 30755 by abdo imad last updated on 25/Feb/18
findlimn→∞n(1+1n)(1+2n)...(1+nn)
Commented by abdo imad last updated on 28/Feb/18
letputAn=n(1+1n)(1+2n)....(1+nn)wehaveln(An)=1nln(∏k=1n(1+kn))=1n∑k=1nln(1+kn)soln(An)isaRiemansumandlimn→∞ln(An)=∫01ln(1+x)dx=∫12ln(t)dt=[tlnt−t]12=2ln2−2+1=2ln2−1⇒limn→∞An=e−1eln(4)=4e.
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