Question and Answers Forum

All Questions      Topic List

None Questions

Previous in All Question      Next in All Question      

Previous in None      Next in None      

Question Number 30813 by mondodotto@gmail.com last updated on 26/Feb/18

Answered by ajfour last updated on 26/Feb/18

y^2 =zx , 5y=2(x+z) =2(70−y) ⇒ y=20 x and z are roots of p^2 −50p−400=0 or (p−25)^2 =15^2 ⇒ x, z = 25±15 .

y2=zx,5y=2(x+z)=2(70−y)⇒y=20xandzarerootsofp2−50p−400=0or(p−25)2=152⇒x,z=25±15.

Terms of Service

Privacy Policy

Contact: info@tinkutara.com