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Question Number 30856 by Joel578 last updated on 27/Feb/18

Commented by mrW2 last updated on 28/Feb/18

$$Questioniswrong.Itshouldbe:$$$${\sin }^{4}A=...$$

Answered by MJS last updated on 27/Feb/18

$$\mathrm{none}\mathrm{of}\mathrm{these}$$$$\frac{1}{2}\cos 2A={\cos }^{2}A-\frac{1}{2}=U$$$$\frac{1}{8}\cos 4A=\frac{1}{8}-{\sin }^{2}A{\cos }^{2}A=V$$$$U+V={\cos }^{4}A-\frac{3}{8}$$$$U-V=\frac{3}{8}-{\sin }^{4}A$$

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