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Question Number 30860 by ajfour last updated on 27/Feb/18

S= 3(1!)−4(2!)+5(3!)−6(4!)+.... .....−(2008)(2006!)+2007! Find value of S.

S=3(1!)−4(2!)+5(3!)−6(4!)+.........−(2008)(2006!)+2007!FindvalueofS.

Answered by MJS last updated on 27/Feb/18

3∙1!−4∙2!=−5 [=−(3!−1)] ...+5∙3!=25 [=4!+1] ...−6∙4!=−119 [=−(5!−1)] ...+7∙5!=721 [=6!+1] ... ...−2008∙2006!=−(2007!−1) ...+2007!=1

3⋅1!−4⋅2!=−5[=−(3!−1)]...+5⋅3!=25[=4!+1]...−6⋅4!=−119[=−(5!−1)]...+7⋅5!=721[=6!+1]......−2008⋅2006!=−(2007!−1)...+2007!=1

Commented by ajfour last updated on 27/Feb/18

Great! Thanks.

Great!Thanks.

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