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Question Number 30957 by Tinkutara last updated on 01/Mar/18

Answered by ajfour last updated on 01/Mar/18

mvr=((nh)/(2π))  T=((2πr)/v) = ((2πr)/((((nh)/(2πmr))))) = ((4π^2 mr^2 )/(nh)) .

$${mvr}=\frac{{nh}}{\mathrm{2}\pi} \\ $$$${T}=\frac{\mathrm{2}\pi{r}}{{v}}\:=\:\frac{\mathrm{2}\pi{r}}{\left(\frac{{nh}}{\mathrm{2}\pi{mr}}\right)}\:=\:\frac{\mathrm{4}\pi^{\mathrm{2}} {mr}^{\mathrm{2}} }{{nh}}\:. \\ $$

Commented by Tinkutara last updated on 01/Mar/18

Yes do you think options are wrong?

Commented by ajfour last updated on 01/Mar/18

yes .

$${yes}\:. \\ $$

Commented by Tinkutara last updated on 01/Mar/18

�� Thanks!

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