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Question Number 30986 by mondodotto@gmail.com last updated on 01/Mar/18

Answered by rahul 19 last updated on 01/Mar/18

$$y=mx+c...\left(1\right)$$$$x^2+y^2=a^2...\left(2\right)$$$$putthevalueofyin{eq}^{n}2,$$$$x^2+{(mx+c)}^2=a^2$$$$\Rightarrow x^2(1+m^2)+2mcx+c^2-a^2=0$$$$D=0aslinetouchesthecircle,$$$$\Rightarrow b^2-4ac=0$$$$\Rightarrow b^2=4ac$$$$\Rightarrow 4m^2{c}^2=4(1+m^2)(c^2-a^2)$$$$\Rightarrow c^2=a^2(1+m^2).$$

Commented by mondodotto@gmail.com last updated on 01/Mar/18

$$\mathrm{thanx}\mathrm{but}\mathrm{what}\mathrm{u}\mathrm{mean}$$$$\mathrm{D}=0\mathrm{D}\mathrm{stand}\mathrm{for}\mathrm{what}?$$

Commented by rahul 19 last updated on 01/Mar/18

$$discriminantofaquadratic{eq}^n.$$

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