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Question Number 31188 by mondodotto@gmail.com last updated on 03/Mar/18

Commented by Tinkutara last updated on 03/Mar/18

$$\tan \theta =\frac{4}{3}$$$$\sin \theta =\pm \frac{4}{5};\cos \theta =\pm \frac{3}{5}$$$$\pm \frac{3}{5}=1-{2\sin }^2\frac{\theta }{2}$$$${\sin }^2\frac{\theta }{2}=\frac{1}{5}$$$$\sin \frac{\theta }{2}=\frac{1}{\sqrt{5}}[\because 0⩽\frac{\theta }{2}⩽\pi ]$$$$\cos \frac{\theta }{2}=\pm \frac{2}{\sqrt{5}}$$$$\tan \frac{\theta }{2}=\pm \frac{1}{2}$$

Commented by mondodotto@gmail.com last updated on 03/Mar/18

$$\mathrm{i}\mathrm{still}{\mathrm{don}}^{\prime }\mathrm{t}\mathrm{get}\mathrm{you}\mathrm{sir}$$

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