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Question Number 31320 by Joel578 last updated on 06/Mar/18
Letpandqaretherootsofx2−2mx−5n=0andmandnaretherootsofx2−2px−5q=0Ifp≠q≠m≠n,thenthevalueofp+q+m+nis...
Answered by MJS last updated on 06/Mar/18
(x−p)(x−q)=x2−2mx−5nx2−(p+q)x+pq=x2−2mx−5np+q=2m;pq=−5nm=p+q2;n=−pq5(x−m)(x−n)=x2−2px−5qx2−(m+n)x+mn=x2−2px−5qm+n=2p;mn=−5qp+q2−pq5=2p⇒p=5q15+2qp+q2×pq5=5q⇒q(p2+pq−50)=0⇒⇒q1=0;p1=0:notvalid(p≠q)p2+pq−50=0withp=5q15+2qq3−10q2−300q−1225=0tryall±qwithq∣1225⇒q2=−5;p2=−5;notvalid(p≠q)q2−15q−225=0q3=152(1−5);p3=52(3+5)m3=52(3−5);n3=152(1+5)q4=n3;p4=m3m+n+p+q=30
Commented by Joel578 last updated on 06/Mar/18
thankyouverymuch
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