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Question Number 31329 by Tinkutara last updated on 06/Mar/18

Commented by Tinkutara last updated on 06/Mar/18

Commented by Tinkutara last updated on 06/Mar/18

Answer given for (iii) part is 4.5 cm/s^2. Is it correct?

Commented by ajfour last updated on 06/Mar/18

$$a_C={\omega }^2\left(\frac{l}{2}\right)=\frac{v_C^2}{\left(l/2\right)}=\frac{{\left(15/2\right)}^2{cm}^2/s^2}{25cm}$$$$=\frac{225}{100}cm/s^2=2.25cm/s^2.$$

Commented by Tinkutara last updated on 06/Mar/18

Is it wrong in book❓

Commented by MJS last updated on 06/Mar/18

$${\mathrm{I}}^{\prime }\mathrm{m}\mathrm{not}\mathrm{sure},\mathrm{but}\mathrm{it}\mathrm{should}\mathrm{be}$$$$l_C=25cm\Rightarrow \frac{l_C}{2}=12.5cm$$$$\Rightarrow a_C=4.5cm/s^2$$$$\mathrm{please}\mathrm{correct}\mathrm{me}\mathrm{if}{\mathrm{I}}^{\prime }\mathrm{m}\mathrm{wrong}$$

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